Base | Representation |
---|---|
bin | 11011010011110111001110… |
… | …010001000110001101110011 |
3 | 120202021121122012102120102011 |
4 | 123103313032101012031303 |
5 | 111220404312040133133 |
6 | 1103242443110503351 |
7 | 34204551544134466 |
oct | 3323671621061563 |
9 | 522247565376364 |
10 | 120112221021043 |
11 | 352a93414a12a9 |
12 | 1157a677964b57 |
13 | 52036c2b082c4 |
14 | 21936692032dd |
15 | dd45db71d6cd |
hex | 6d3dce446373 |
120112221021043 has 2 divisors, whose sum is σ = 120112221021044. Its totient is φ = 120112221021042.
The previous prime is 120112221021019. The next prime is 120112221021053. The reversal of 120112221021043 is 340120122211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120112221021043 - 25 = 120112221021011 is a prime.
It is not a weakly prime, because it can be changed into another prime (120112221021053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056110510521 + 60056110510522.
It is an arithmetic number, because the mean of its divisors is an integer number (60056110510522).
Almost surely, 2120112221021043 is an apocalyptic number.
120112221021043 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112221021043 is an equidigital number, since it uses as much as digits as its factorization.
120112221021043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 120112221021043 its reverse (340120122211021), we get a palindrome (460232343232064).
The spelling of 120112221021043 in words is "one hundred twenty trillion, one hundred twelve billion, two hundred twenty-one million, twenty-one thousand, forty-three".
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