Base | Representation |
---|---|
bin | 11011010011110111001110… |
… | …010001110010011010110110 |
3 | 120202021121122012202202210001 |
4 | 123103313032101302122312 |
5 | 111220404312111431402 |
6 | 1103242443114421514 |
7 | 34204551545520403 |
oct | 3323671621623266 |
9 | 522247565682701 |
10 | 120112221202102 |
11 | 352a9341605338 |
12 | 1157a677a3189a |
13 | 52036c2b6c83c |
14 | 219366924d2aa |
15 | dd45db757187 |
hex | 6d3dce4726b6 |
120112221202102 has 4 divisors (see below), whose sum is σ = 180168331803156. Its totient is φ = 60056110601050.
The previous prime is 120112221202097. The next prime is 120112221202109. The reversal of 120112221202102 is 201202122211021.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1201122212021023 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120112221202102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120112221202109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30028055300524 + ... + 30028055300527.
It is an arithmetic number, because the mean of its divisors is an integer number (45042082950789).
Almost surely, 2120112221202102 is an apocalyptic number.
120112221202102 is a deficient number, since it is larger than the sum of its proper divisors (60056110601054).
120112221202102 is an equidigital number, since it uses as much as digits as its factorization.
120112221202102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60056110601053.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 120112221202102 its reverse (201202122211021), we get a palindrome (321314343413123).
The spelling of 120112221202102 in words is "one hundred twenty trillion, one hundred twelve billion, two hundred twenty-one million, two hundred two thousand, one hundred two".
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