Base | Representation |
---|---|
bin | 1010111011001001010010… |
… | …1000011111011001111111 |
3 | 1120112021001201122000211221 |
4 | 2232302110220133121333 |
5 | 3033242440340430413 |
6 | 41313513532454211 |
7 | 2346532166112364 |
oct | 256622450373177 |
9 | 46467051560757 |
10 | 12011222201983 |
11 | 3910a2688a2a4 |
12 | 141ba3201a367 |
13 | 691865675ca4 |
14 | 2d74bc1b046b |
15 | 15c68d25268d |
hex | aec94a1f67f |
12011222201983 has 4 divisors (see below), whose sum is σ = 12098895356880. Its totient is φ = 11923549047088.
The previous prime is 12011222201971. The next prime is 12011222202017. The reversal of 12011222201983 is 38910222211021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12011222201983 - 29 = 12011222201471 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12011222501983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43836577243 + ... + 43836577516.
It is an arithmetic number, because the mean of its divisors is an integer number (3024723839220).
Almost surely, 212011222201983 is an apocalyptic number.
12011222201983 is a deficient number, since it is larger than the sum of its proper divisors (87673154897).
12011222201983 is an equidigital number, since it uses as much as digits as its factorization.
12011222201983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87673154896.
The product of its (nonzero) digits is 6912, while the sum is 34.
The spelling of 12011222201983 in words is "twelve trillion, eleven billion, two hundred twenty-two million, two hundred one thousand, nine hundred eighty-three".
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