Base | Representation |
---|---|
bin | 1010111011001001101010… |
… | …0101100111110011001011 |
3 | 1120112021022200122001022101 |
4 | 2232302122211213303023 |
5 | 3033243141430110402 |
6 | 41313531502134231 |
7 | 2346534521254663 |
oct | 256623245476313 |
9 | 46467280561271 |
10 | 12011322113227 |
11 | 3910a78220078 |
12 | 141ba5b581377 |
13 | 691880288278 |
14 | 2d74cb57b1a3 |
15 | 15c696ddab87 |
hex | aec9a967ccb |
12011322113227 has 2 divisors, whose sum is σ = 12011322113228. Its totient is φ = 12011322113226.
The previous prime is 12011322113191. The next prime is 12011322113233. The reversal of 12011322113227 is 72231122311021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12011322113227 - 219 = 12011321588939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12011322113195 and 12011322113204.
It is not a weakly prime, because it can be changed into another prime (12011322113027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005661056613 + 6005661056614.
It is an arithmetic number, because the mean of its divisors is an integer number (6005661056614).
Almost surely, 212011322113227 is an apocalyptic number.
12011322113227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011322113227 is an equidigital number, since it uses as much as digits as its factorization.
12011322113227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 12011322113227 its reverse (72231122311021), we get a palindrome (84242444424248).
The spelling of 12011322113227 in words is "twelve trillion, eleven billion, three hundred twenty-two million, one hundred thirteen thousand, two hundred twenty-seven".
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