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12011330003201 is a prime number
BaseRepresentation
bin1010111011001001101100…
…0011101110000100000001
31120112021100020110220022122
42232302123003232010001
53033243200440100301
641313532343214025
72346534645315554
oct256623303560401
946467306426278
1012011330003201
113910a81719a11
12141ba62147315
13691881abb5a9
142d74cc63269b
1515c69794881b
hexaec9b0ee101

12011330003201 has 2 divisors, whose sum is σ = 12011330003202. Its totient is φ = 12011330003200.

The previous prime is 12011330003171. The next prime is 12011330003297. The reversal of 12011330003201 is 10230003311021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12010376428801 + 953574400 = 3465599^2 + 30880^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011330003201 - 222 = 12011325808897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12011330003201.

It is not a weakly prime, because it can be changed into another prime (12011330005201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005665001600 + 6005665001601.

It is an arithmetic number, because the mean of its divisors is an integer number (6005665001601).

Almost surely, 212011330003201 is an apocalyptic number.

It is an amenable number.

12011330003201 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011330003201 is an equidigital number, since it uses as much as digits as its factorization.

12011330003201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12011330003201 its reverse (10230003311021), we get a palindrome (22241333314222).

The spelling of 12011330003201 in words is "twelve trillion, eleven billion, three hundred thirty million, three thousand, two hundred one".