Base | Representation |
---|---|
bin | 1010111011001001101101… |
… | …0100100111111010000001 |
3 | 1120112021100112211000211100 |
4 | 2232302123110213322001 |
5 | 3033243203103400213 |
6 | 41313533022205013 |
7 | 2346535031062605 |
oct | 256623324477201 |
9 | 46467315730740 |
10 | 12011334434433 |
11 | 3910a84176194 |
12 | 141ba63723769 |
13 | 6918829b0519 |
14 | 2d74cd067505 |
15 | 15c698021773 |
hex | aec9b527e81 |
12011334434433 has 24 divisors (see below), whose sum is σ = 17462214493568. Its totient is φ = 7955640662112.
The previous prime is 12011334434383. The next prime is 12011334434471. The reversal of 12011334434433 is 33443443311021.
12011334434433 is a `hidden beast` number, since 1 + 20 + 1 + 133 + 44 + 34 + 433 = 666.
It is not a de Polignac number, because 12011334434433 - 210 = 12011334433409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12011334434233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11955816 + ... + 12921462.
Almost surely, 212011334434433 is an apocalyptic number.
It is an amenable number.
12011334434433 is a deficient number, since it is larger than the sum of its proper divisors (5450880059135).
12011334434433 is a wasteful number, since it uses less digits than its factorization.
12011334434433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 974613 (or 974610 counting only the distinct ones).
The product of its (nonzero) digits is 124416, while the sum is 36.
Adding to 12011334434433 its reverse (33443443311021), we get a palindrome (45454777745454).
The spelling of 12011334434433 in words is "twelve trillion, eleven billion, three hundred thirty-four million, four hundred thirty-four thousand, four hundred thirty-three".
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