Base | Representation |
---|---|
bin | 110111111011101010… |
… | …0010101110010111011 |
3 | 102111000220121000112201 |
4 | 1233313110111302323 |
5 | 3431443013441444 |
6 | 131102423251031 |
7 | 11451344144221 |
oct | 1576724256273 |
9 | 374026530481 |
10 | 120113421499 |
11 | 46a379933a5 |
12 | 1b3418a9a77 |
13 | b432849b96 |
14 | 5b5642cb11 |
15 | 31cee0bdd4 |
hex | 1bf7515cbb |
120113421499 has 2 divisors, whose sum is σ = 120113421500. Its totient is φ = 120113421498.
The previous prime is 120113421397. The next prime is 120113421541. The reversal of 120113421499 is 994124311021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120113421499 - 27 = 120113421371 is a prime.
It is not a weakly prime, because it can be changed into another prime (120113424499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056710749 + 60056710750.
It is an arithmetic number, because the mean of its divisors is an integer number (60056710750).
Almost surely, 2120113421499 is an apocalyptic number.
120113421499 is a deficient number, since it is larger than the sum of its proper divisors (1).
120113421499 is an equidigital number, since it uses as much as digits as its factorization.
120113421499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 37.
It can be divided in two parts, 12011 and 3421499, that added together give a triangular number (3433510 = T2620).
The spelling of 120113421499 in words is "one hundred twenty billion, one hundred thirteen million, four hundred twenty-one thousand, four hundred ninety-nine".
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