Base | Representation |
---|---|
bin | 10001011110101001101… |
… | …110000100000001110011 |
3 | 11020211100202000210000201 |
4 | 101132221232010001303 |
5 | 124134420141101321 |
6 | 2315444141300031 |
7 | 152531310410551 |
oct | 21365156040163 |
9 | 4224322023021 |
10 | 1201143300211 |
11 | 4234470964a8 |
12 | 174958564617 |
13 | 893624193ca |
14 | 421c82d8bd1 |
15 | 213a0276291 |
hex | 117a9b84073 |
1201143300211 has 2 divisors, whose sum is σ = 1201143300212. Its totient is φ = 1201143300210.
The previous prime is 1201143300187. The next prime is 1201143300229. The reversal of 1201143300211 is 1120033411021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201143300211 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201143900211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600571650105 + 600571650106.
It is an arithmetic number, because the mean of its divisors is an integer number (600571650106).
Almost surely, 21201143300211 is an apocalyptic number.
1201143300211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201143300211 is an equidigital number, since it uses as much as digits as its factorization.
1201143300211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1201143300211 its reverse (1120033411021), we get a palindrome (2321176711232).
The spelling of 1201143300211 in words is "one trillion, two hundred one billion, one hundred forty-three million, three hundred thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •