Base | Representation |
---|---|
bin | 1010111011001010000111… |
… | …0111001000010001110110 |
3 | 1120112021122012020210222211 |
4 | 2232302201313020101312 |
5 | 3033243414200040342 |
6 | 41313551541444034 |
7 | 2346540532432366 |
oct | 256624167102166 |
9 | 46467565223884 |
10 | 12011444143222 |
11 | 3911030099007 |
12 | 141ba9441061a |
13 | 69189c643174 |
14 | 2d74dd8649a6 |
15 | 15c6a2992c17 |
hex | aeca1dc8476 |
12011444143222 has 4 divisors (see below), whose sum is σ = 18017166214836. Its totient is φ = 6005722071610.
The previous prime is 12011444143169. The next prime is 12011444143247. The reversal of 12011444143222 is 22234144411021.
12011444143222 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3002861035804 + ... + 3002861035807.
It is an arithmetic number, because the mean of its divisors is an integer number (4504291553709).
Almost surely, 212011444143222 is an apocalyptic number.
12011444143222 is a deficient number, since it is larger than the sum of its proper divisors (6005722071614).
12011444143222 is an equidigital number, since it uses as much as digits as its factorization.
12011444143222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6005722071613.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 12011444143222 its reverse (22234144411021), we get a palindrome (34245588554243).
The spelling of 12011444143222 in words is "twelve trillion, eleven billion, four hundred forty-four million, one hundred forty-three thousand, two hundred twenty-two".
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