Base | Representation |
---|---|
bin | 1110010100011… |
… | …01100010111001 |
3 | 22101000121010211 |
4 | 13022031202321 |
5 | 221222224213 |
6 | 15530311121 |
7 | 2655660412 |
oct | 712154271 |
9 | 271017124 |
10 | 120117433 |
11 | 61892007 |
12 | 342884a1 |
13 | 1bb68507 |
14 | 11d4a809 |
15 | a82a53d |
hex | 728d8b9 |
120117433 has 2 divisors, whose sum is σ = 120117434. Its totient is φ = 120117432.
The previous prime is 120117407. The next prime is 120117457. The reversal of 120117433 is 334711021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116380944 + 3736489 = 10788^2 + 1933^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120117433 is a prime.
It is not a weakly prime, because it can be changed into another prime (120117463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60058716 + 60058717.
It is an arithmetic number, because the mean of its divisors is an integer number (60058717).
Almost surely, 2120117433 is an apocalyptic number.
It is an amenable number.
120117433 is a deficient number, since it is larger than the sum of its proper divisors (1).
120117433 is an equidigital number, since it uses as much as digits as its factorization.
120117433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
The square root of 120117433 is about 10959.8098979864. The cubic root of 120117433 is about 493.4032594554.
Adding to 120117433 its reverse (334711021), we get a palindrome (454828454).
The spelling of 120117433 in words is "one hundred twenty million, one hundred seventeen thousand, four hundred thirty-three".
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