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120120012022140 = 2232513193347766501
BaseRepresentation
bin11011010011111110011110…
…101001011010000101111100
3120202022100202011120102201100
4123103332132221122011330
5111221021241034202030
61103250212143013100
734205245606430424
oct3323763651320574
9522270664512640
10120120012022140
113530167a29a789
1211580090b9a190
135204364c63120
142193ba7c25484
15dd48e56d3360
hex6d3f9ea5a17c

120120012022140 has 288 divisors, whose sum is σ = 395562346635456. Its totient is φ = 29329993728000.

The previous prime is 120120012022039. The next prime is 120120012022141. The reversal of 120120012022140 is 41220210021021.

120120012022140 is a `hidden beast` number, since 1 + 201 + 200 + 1 + 2 + 0 + 221 + 40 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120120012022141) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 156328890 + ... + 157095390.

It is an arithmetic number, because the mean of its divisors is an integer number (1373480370262).

Almost surely, 2120120012022140 is an apocalyptic number.

120120012022140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120120012022140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (197781173317728).

120120012022140 is an abundant number, since it is smaller than the sum of its proper divisors (275442334613316).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120120012022140 is a wasteful number, since it uses less digits than its factorization.

120120012022140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 767069 (or 767064 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 18.

Adding to 120120012022140 its reverse (41220210021021), we get a palindrome (161340222043161).

The spelling of 120120012022140 in words is "one hundred twenty trillion, one hundred twenty billion, twelve million, twenty-two thousand, one hundred forty".