Base | Representation |
---|---|
bin | 10001011110101101001… |
… | …011010111001000110011 |
3 | 11020211111210012002122212 |
4 | 101132231023113020303 |
5 | 124140030013443212 |
6 | 2315454012522335 |
7 | 152532613455203 |
oct | 21365513271063 |
9 | 4224453162585 |
10 | 1201201312307 |
11 | 423476909887 |
12 | 174973a803ab |
13 | 8937144b5a9 |
14 | 421d1cba403 |
15 | 213a53d4e22 |
hex | 117ad2d7233 |
1201201312307 has 2 divisors, whose sum is σ = 1201201312308. Its totient is φ = 1201201312306.
The previous prime is 1201201312217. The next prime is 1201201312313. The reversal of 1201201312307 is 7032131021021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201201312307 - 216 = 1201201246771 is a prime.
It is a super-3 number, since 3×12012013123073 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1201201312327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600600656153 + 600600656154.
It is an arithmetic number, because the mean of its divisors is an integer number (600600656154).
Almost surely, 21201201312307 is an apocalyptic number.
1201201312307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201201312307 is an equidigital number, since it uses as much as digits as its factorization.
1201201312307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 1201201312307 its reverse (7032131021021), we get a palindrome (8233332333328).
The spelling of 1201201312307 in words is "one trillion, two hundred one billion, two hundred one million, three hundred twelve thousand, three hundred seven".
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