Base | Representation |
---|---|
bin | 110111111011110111… |
… | …1000111100100011001 |
3 | 102111001101210122122102 |
4 | 1233313233013210121 |
5 | 3432001313103423 |
6 | 131103233533145 |
7 | 11451460621451 |
oct | 1576757074431 |
9 | 374041718572 |
10 | 120120441113 |
11 | 46a40948332 |
12 | 1b3441141b5 |
13 | b434136cba |
14 | 5b57338d61 |
15 | 31d0846c28 |
hex | 1bf7bc7919 |
120120441113 has 2 divisors, whose sum is σ = 120120441114. Its totient is φ = 120120441112.
The previous prime is 120120441041. The next prime is 120120441169. The reversal of 120120441113 is 311144021021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67593760144 + 52526680969 = 259988^2 + 229187^2 .
It is an emirp because it is prime and its reverse (311144021021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120120441113 - 28 = 120120440857 is a prime.
It is not a weakly prime, because it can be changed into another prime (120120441613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060220556 + 60060220557.
It is an arithmetic number, because the mean of its divisors is an integer number (60060220557).
Almost surely, 2120120441113 is an apocalyptic number.
It is an amenable number.
120120441113 is a deficient number, since it is larger than the sum of its proper divisors (1).
120120441113 is an equidigital number, since it uses as much as digits as its factorization.
120120441113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 120120441113 its reverse (311144021021), we get a palindrome (431264462134).
The spelling of 120120441113 in words is "one hundred twenty billion, one hundred twenty million, four hundred forty-one thousand, one hundred thirteen".
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