Base | Representation |
---|---|
bin | 10110010111111100… |
… | …11101101101110011 |
3 | 1011000010212002121002 |
4 | 23023332131231303 |
5 | 144100043142313 |
6 | 5303540352215 |
7 | 603446013206 |
oct | 131376355563 |
9 | 34003762532 |
10 | 12012084083 |
11 | 510456561a |
12 | 23b29a566b |
13 | 1195805b7c |
14 | 81d48593d |
15 | 4a485b058 |
hex | 2cbf9db73 |
12012084083 has 2 divisors, whose sum is σ = 12012084084. Its totient is φ = 12012084082.
The previous prime is 12012084037. The next prime is 12012084109. The reversal of 12012084083 is 38048021021.
It is a strong prime.
It is an emirp because it is prime and its reverse (38048021021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12012084083 - 216 = 12012018547 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12012084023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006042041 + 6006042042.
It is an arithmetic number, because the mean of its divisors is an integer number (6006042042).
Almost surely, 212012084083 is an apocalyptic number.
12012084083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012084083 is an equidigital number, since it uses as much as digits as its factorization.
12012084083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 29.
The spelling of 12012084083 in words is "twelve billion, twelve million, eighty-four thousand, eighty-three".
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