12012100211221 has 4 divisors (see below), whose sum is σ = 13104109321344. Its totient is φ = 10920091101100.

The previous prime is 12012100211213. The next prime is 12012100211239. The reversal of 12012100211221 is 12211200121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12012100211221 - 2³ = 12012100211213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012100211195 and 12012100211204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012100211281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546004555045 + ... + 546004555066.

It is an arithmetic number, because the mean of its divisors is an integer number (3276027330336).

Almost surely, 2^{12012100211221} is an apocalyptic number.

12012100211221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12012100211221 is a deficient number, since it is larger than the sum of its proper divisors (1092009110123).

12012100211221 is a wasteful number, since it uses less digits than its factorization.

12012100211221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1092009110122.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 12012100211221 its reverse (12211200121021), we get a palindrome (24223300332242).

The spelling of 12012100211221 in words is "twelve trillion, twelve billion, one hundred million, two hundred eleven thousand, two hundred twenty-one".