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120121010849857 is a prime number
BaseRepresentation
bin11011010011111111011010…
…001011101000100001000001
3120202022110022210001010202111
4123103333122023220201001
5111221030312234143412
61103250455223215321
734205312425346533
oct3323773213504101
9522273283033674
10120121010849857
1135302042092836
121158030b5a7541
135204493b7c844
142193c60749853
15dd49532322a7
hex6d3fda2e8841

120121010849857 has 2 divisors, whose sum is σ = 120121010849858. Its totient is φ = 120121010849856.

The previous prime is 120121010849831. The next prime is 120121010849897. The reversal of 120121010849857 is 758948010121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93898735698496 + 26222275151361 = 9690136^2 + 5120769^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120121010849857 is a prime.

It is a super-2 number, since 2×1201210108498572 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120121010849857.

It is not a weakly prime, because it can be changed into another prime (120121010849897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060505424928 + 60060505424929.

It is an arithmetic number, because the mean of its divisors is an integer number (60060505424929).

Almost surely, 2120121010849857 is an apocalyptic number.

It is an amenable number.

120121010849857 is a deficient number, since it is larger than the sum of its proper divisors (1).

120121010849857 is an equidigital number, since it uses as much as digits as its factorization.

120121010849857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 322560, while the sum is 49.

The spelling of 120121010849857 in words is "one hundred twenty trillion, one hundred twenty-one billion, ten million, eight hundred forty-nine thousand, eight hundred fifty-seven".