12012101401300 has 432 divisors, whose sum is σ = 35306846217216. Its totient is φ = 3451751424000.

The previous prime is 12012101401271. The next prime is 12012101401303. The reversal of 12012101401300 is 310410121021.

12012101401300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×12012101401300² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012101401303) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 950242980 + ... + 950255620.

It is an arithmetic number, because the mean of its divisors is an integer number (81728810688).

Almost surely, 2^{12012101401300} is an apocalyptic number.

12012101401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12012101401300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17653423108608).

12012101401300 is an abundant number, since it is smaller than the sum of its proper divisors (23294744815916).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012101401300 is a wasteful number, since it uses less digits than its factorization.

12012101401300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13560 (or 13542 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12012101401300 its reverse (310410121021), we get a palindrome (12322511522321).

The spelling of 12012101401300 in words is "twelve trillion, twelve billion, one hundred one million, four hundred one thousand, three hundred".