1201210211017 has 2 divisors, whose sum is σ = 1201210211018. Its totient is φ = 1201210211016.

The previous prime is 1201210210997. The next prime is 1201210211051. The reversal of 1201210211017 is 7101120121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 623809313856 + 577400897161 = 789816^2 + 759869^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201210211017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201210210985 and 1201210211003.

It is not a weakly prime, because it can be changed into another prime (1201210211057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600605105508 + 600605105509.

It is an arithmetic number, because the mean of its divisors is an integer number (600605105509).

Almost surely, 2^{1201210211017} is an apocalyptic number.

It is an amenable number.

1201210211017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201210211017 is an equidigital number, since it uses as much as digits as its factorization.

1201210211017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1201210211017 its reverse (7101120121021), we get a palindrome (8302330332038).

The spelling of 1201210211017 in words is "one trillion, two hundred one billion, two hundred ten million, two hundred eleven thousand, seventeen".