Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …000010110101111011011 |
3 | 11020211112110102210102002 |
4 | 101132231300112233123 |
5 | 124140040004310021 |
6 | 2315455000431215 |
7 | 152533062055325 |
oct | 21365560265733 |
9 | 4224473383362 |
10 | 1201211010011 |
11 | 423481332911 |
12 | 17497717850b |
13 | 8937346568c |
14 | 421d32c2615 |
15 | 213a619d50b |
hex | 117adc16bdb |
1201211010011 has 2 divisors, whose sum is σ = 1201211010012. Its totient is φ = 1201211010010.
The previous prime is 1201211009993. The next prime is 1201211010023. The reversal of 1201211010011 is 1100101121021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201211010011 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201211009974 and 1201211010001.
It is not a weakly prime, because it can be changed into another prime (1201211016011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600605505005 + 600605505006.
It is an arithmetic number, because the mean of its divisors is an integer number (600605505006).
Almost surely, 21201211010011 is an apocalyptic number.
1201211010011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201211010011 is an equidigital number, since it uses as much as digits as its factorization.
1201211010011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1201211010011 its reverse (1100101121021), we get a palindrome (2301312131032).
The spelling of 1201211010011 in words is "one trillion, two hundred one billion, two hundred eleven million, ten thousand, eleven".
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