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12012111002103 = 38352392239789
BaseRepresentation
bin1010111011001100100110…
…0110111111100111110111
31120112100100200001202101220
42232303021212333213313
53033301300404031403
641314142042521423
72346563210563362
oct256631146774767
946470320052356
1012012111002103
113911342561a53
12142003b806273
1369197784a914
142d75642530d9
1515c6e12ba953
hexaecc99bf9f7

12012111002103 has 16 divisors (see below), whose sum is σ = 16240106386560. Its totient is φ = 7896463771104.

The previous prime is 12012111002069. The next prime is 12012111002131. The reversal of 12012111002103 is 30120011121021.

It is not a de Polignac number, because 12012111002103 - 230 = 12011037260279 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012111002153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45989668 + ... + 46250121.

It is an arithmetic number, because the mean of its divisors is an integer number (1015006649160).

Almost surely, 212012111002103 is an apocalyptic number.

12012111002103 is a deficient number, since it is larger than the sum of its proper divisors (4227995384457).

12012111002103 is an equidigital number, since it uses as much as digits as its factorization.

12012111002103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92240398.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 12012111002103 its reverse (30120011121021), we get a palindrome (42132122123124).

The spelling of 12012111002103 in words is "twelve trillion, twelve billion, one hundred eleven million, two thousand, one hundred three".

Divisors: 1 3 83 249 523 1569 43409 130227 92239789 276719367 7655902487 22967707461 48241409647 144724228941 4004037000701 12012111002103