Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …100001101010100101101 |
3 | 11020211112112100002212120 |
4 | 101132231310031110231 |
5 | 124140040234120023 |
6 | 2315455034223153 |
7 | 152533103463045 |
oct | 21365564152455 |
9 | 4224475302776 |
10 | 1201212020013 |
11 | 423481962725 |
12 | 174977584ab9 |
13 | 8937372a305 |
14 | 421d34a6725 |
15 | 213a62ec8e3 |
hex | 117add0d52d |
1201212020013 has 32 divisors (see below), whose sum is σ = 1718082804096. Its totient is φ = 743874582528.
The previous prime is 1201212020003. The next prime is 1201212020033. The reversal of 1201212020013 is 3100202121021.
It is not a de Polignac number, because 1201212020013 - 216 = 1201211954477 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201212019974 and 1201212020001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201212020003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 711870 + ... + 1705632.
It is an arithmetic number, because the mean of its divisors is an integer number (53690087628).
Almost surely, 21201212020013 is an apocalyptic number.
It is an amenable number.
1201212020013 is a deficient number, since it is larger than the sum of its proper divisors (516870784083).
1201212020013 is a wasteful number, since it uses less digits than its factorization.
1201212020013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 994093.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1201212020013 its reverse (3100202121021), we get a palindrome (4301414141034).
The spelling of 1201212020013 in words is "one trillion, two hundred one billion, two hundred twelve million, twenty thousand, thirteen".
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