Base | Representation |
---|---|
bin | 1010111011001100101000… |
… | …1101101000100000011000 |
3 | 1120112100101101010100200102 |
4 | 2232303022031220200120 |
5 | 3033301311002143112 |
6 | 41314143043554532 |
7 | 2346563362640651 |
oct | 256631215504030 |
9 | 46470341110612 |
10 | 12012121131032 |
11 | 391134824aa70 |
12 | 142004308ba48 |
13 | 691979986079 |
14 | 2d756572c528 |
15 | 15c6e211bbc2 |
hex | aecca368818 |
12012121131032 has 16 divisors (see below), whose sum is σ = 24570247768200. Its totient is φ = 5460055059520.
The previous prime is 12012121130969. The next prime is 12012121131037. The reversal of 12012121131032 is 23013112121021.
It is a junction number, because it is equal to n+sod(n) for n = 12012121130995 and 12012121131013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12012121131037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68250688157 + ... + 68250688332.
Almost surely, 212012121131032 is an apocalyptic number.
It is an amenable number.
12012121131032 is an abundant number, since it is smaller than the sum of its proper divisors (12558126637168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012121131032 is a wasteful number, since it uses less digits than its factorization.
12012121131032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 136501376506 (or 136501376502 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 12012121131032 its reverse (23013112121021), we get a palindrome (35025233252053).
The spelling of 12012121131032 in words is "twelve trillion, twelve billion, one hundred twenty-one million, one hundred thirty-one thousand, thirty-two".
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