Base | Representation |
---|---|
bin | 11011010011111111101011… |
… | …011010101001110100001100 |
3 | 120202022111001221010111012111 |
4 | 123103333223122221310030 |
5 | 111221031410300000022 |
6 | 1103250544032513404 |
7 | 34205322536160103 |
oct | 3323775332516414 |
9 | 522274057114174 |
10 | 120121300000012 |
11 | 35302180326603 |
12 | 115803903ab864 |
13 | 520450ba4bccc |
14 | 2193c8acd703a |
15 | dd496d7eb477 |
hex | 6d3feb6a9d0c |
120121300000012 has 24 divisors (see below), whose sum is σ = 210286778667840. Its totient is φ = 60039365589840.
The previous prime is 120121299999997. The next prime is 120121300000021. The reversal of 120121300000012 is 210000003121021.
It is a super-2 number, since 2×1201213000000122 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120121299999938 and 120121300000001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 210669439 + ... + 211238857.
It is an arithmetic number, because the mean of its divisors is an integer number (8761949111160).
Almost surely, 2120121300000012 is an apocalyptic number.
It is an amenable number.
120121300000012 is a deficient number, since it is larger than the sum of its proper divisors (90165478667828).
120121300000012 is a wasteful number, since it uses less digits than its factorization.
120121300000012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 588021 (or 588019 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 120121300000012 its reverse (210000003121021), we get a palindrome (330121303121033).
The spelling of 120121300000012 in words is "one hundred twenty trillion, one hundred twenty-one billion, three hundred million, twelve", and thus it is an aban number.
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