120121300000033 has 2 divisors, whose sum is σ = 120121300000034. Its totient is φ = 120121300000032.

The previous prime is 120121300000021. The next prime is 120121300000109. The reversal of 120121300000033 is 330000003121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119544221242384 + 577078757649 = 10933628^2 + 759657^2 .

It is a cyclic number.

It is not a de Polignac number, because 120121300000033 - 2²⁹ = 120120763129121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120121299999962 and 120121300000016.

It is not a weakly prime, because it can be changed into another prime (120121300000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060650000016 + 60060650000017.

It is an arithmetic number, because the mean of its divisors is an integer number (60060650000017).

Almost surely, 2^{120121300000033} is an apocalyptic number.

It is an amenable number.

120121300000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

120121300000033 is an equidigital number, since it uses as much as digits as its factorization.

120121300000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 120121300000033 its reverse (330000003121021), we get a palindrome (450121303121054).

The spelling of 120121300000033 in words is "one hundred twenty trillion, one hundred twenty-one billion, three hundred million, thirty-three", and thus it is an aban number.