Base | Representation |
---|---|
bin | 10110010111111101… |
… | …01001010000110001 |
3 | 1011000010221111110201 |
4 | 23023332221100301 |
5 | 144100101201002 |
6 | 5303541355201 |
7 | 603446301121 |
oct | 131376512061 |
9 | 34003844421 |
10 | 12012131377 |
11 | 5104598104 |
12 | 23b2a08b01 |
13 | 119582155c |
14 | 81d498c81 |
15 | 4a486a087 |
hex | 2cbfa9431 |
12012131377 has 2 divisors, whose sum is σ = 12012131378. Its totient is φ = 12012131376.
The previous prime is 12012131323. The next prime is 12012131423. The reversal of 12012131377 is 77313121021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8478542241 + 3533589136 = 92079^2 + 59444^2 .
It is a cyclic number.
It is not a de Polignac number, because 12012131377 - 231 = 9864647729 is a prime.
It is a super-2 number, since 2×120121313772 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12012131077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006065688 + 6006065689.
It is an arithmetic number, because the mean of its divisors is an integer number (6006065689).
Almost surely, 212012131377 is an apocalyptic number.
It is an amenable number.
12012131377 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012131377 is an equidigital number, since it uses as much as digits as its factorization.
12012131377 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1764, while the sum is 28.
Adding to 12012131377 its reverse (77313121021), we get a palindrome (89325252398).
The spelling of 12012131377 in words is "twelve billion, twelve million, one hundred thirty-one thousand, three hundred seventy-seven".
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