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120121322010000 = 2435414092841763
BaseRepresentation
bin11011010011111111101100…
…101110100111010110010000
3120202022111010110112201020020
4123103333230232213112100
5111221031431413310000
61103250550140343440
734205323224230133
oct3323775456472620
9522274113481206
10120121322010000
1135302191799a83
1211580397844b80
13520451348727c
142193c8dbc621a
15dd49706e7ba0
hex6d3fecba7590

120121322010000 has 200 divisors, whose sum is σ = 388042987870560. Its totient is φ = 32009607168000.

The previous prime is 120121322009957. The next prime is 120121322010043. The reversal of 120121322010000 is 10223121021.

It is an interprime number because it is at equal distance from previous prime (120121322009957) and next prime (120121322010043).

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×1201213220100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 40849119 + ... + 43690881.

Almost surely, 2120121322010000 is an apocalyptic number.

120121322010000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120121322010000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (194021493935280).

120121322010000 is an abundant number, since it is smaller than the sum of its proper divisors (267921665860560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120121322010000 is a wasteful number, since it uses less digits than its factorization.

120121322010000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2843203 (or 2843182 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 120121322010000 its reverse (10223121021), we get a palindrome (120131545131021).

The spelling of 120121322010000 in words is "one hundred twenty trillion, one hundred twenty-one billion, three hundred twenty-two million, ten thousand".