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12012201121313 is a prime number
BaseRepresentation
bin1010111011001100111011…
…1110110001011000100001
31120112100120221122021201102
42232303032332301120201
53033301441441340223
641314155022244145
72346565353563531
oct256631676613041
946470527567642
1012012201121313
113911389414938
121420065a26655
13691990411bb3
142d75721d14c1
1515c6e916c928
hexaeccefb1621

12012201121313 has 2 divisors, whose sum is σ = 12012201121314. Its totient is φ = 12012201121312.

The previous prime is 12012201121289. The next prime is 12012201121321. The reversal of 12012201121313 is 31312110221021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11841361912384 + 170839208929 = 3441128^2 + 413327^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012201121313 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12012201121373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006100560656 + 6006100560657.

It is an arithmetic number, because the mean of its divisors is an integer number (6006100560657).

Almost surely, 212012201121313 is an apocalyptic number.

It is an amenable number.

12012201121313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012201121313 is an equidigital number, since it uses as much as digits as its factorization.

12012201121313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 12012201121313 its reverse (31312110221021), we get a palindrome (43324311342334).

The spelling of 12012201121313 in words is "twelve trillion, twelve billion, two hundred one million, one hundred twenty-one thousand, three hundred thirteen".