Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …110110110011001100001 |
3 | 11020211120011102110212002 |
4 | 101132232112312121201 |
5 | 124140100100214103 |
6 | 2315500001013345 |
7 | 152533243614503 |
oct | 21365626663141 |
9 | 4224504373762 |
10 | 1201221101153 |
11 | 423486aa54a7 |
12 | 17497a624255 |
13 | 89375589878 |
14 | 421d478bd73 |
15 | 213a6ee3488 |
hex | 117ae5b6661 |
1201221101153 has 2 divisors, whose sum is σ = 1201221101154. Its totient is φ = 1201221101152.
The previous prime is 1201221101099. The next prime is 1201221101191. The reversal of 1201221101153 is 3511011221021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1006905881809 + 194315219344 = 1003447^2 + 440812^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201221101153 - 28 = 1201221100897 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201221101053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610550576 + 600610550577.
It is an arithmetic number, because the mean of its divisors is an integer number (600610550577).
Almost surely, 21201221101153 is an apocalyptic number.
It is an amenable number.
1201221101153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201221101153 is an equidigital number, since it uses as much as digits as its factorization.
1201221101153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 1201221101153 its reverse (3511011221021), we get a palindrome (4712232322174).
The spelling of 1201221101153 in words is "one trillion, two hundred one billion, two hundred twenty-one million, one hundred one thousand, one hundred fifty-three".
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