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120122129993 is a prime number
BaseRepresentation
bin110111111011111010…
…1100011111001001001
3102111001111222110100112
41233313311203321021
53432002231124433
6131103334044105
711451511154345
oct1576765437111
9374044873315
10120122129993
1146a418a11a8
121b3447a9635
13b4345a8938
145b57658625
1531d0a7c348
hex1bf7d63e49

120122129993 has 2 divisors, whose sum is σ = 120122129994. Its totient is φ = 120122129992.

The previous prime is 120122129957. The next prime is 120122130013. The reversal of 120122129993 is 399921221021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83666719504 + 36455410489 = 289252^2 + 190933^2 .

It is a cyclic number.

It is not a de Polignac number, because 120122129993 - 26 = 120122129929 is a prime.

It is a super-2 number, since 2×1201221299932 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 120122129993.

It is not a weakly prime, because it can be changed into another prime (120122129093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061064996 + 60061064997.

It is an arithmetic number, because the mean of its divisors is an integer number (60061064997).

Almost surely, 2120122129993 is an apocalyptic number.

It is an amenable number.

120122129993 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122129993 is an equidigital number, since it uses as much as digits as its factorization.

120122129993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 41.

The spelling of 120122129993 in words is "one hundred twenty billion, one hundred twenty-two million, one hundred twenty-nine thousand, nine hundred ninety-three".