Base | Representation |
---|---|
bin | 11011010100000000100010… |
… | …010000001011001100000011 |
3 | 120202022120110001021022221020 |
4 | 123110000202100023030003 |
5 | 111221040301310000003 |
6 | 1103251215215400523 |
7 | 34205354410064604 |
oct | 3324004220131403 |
9 | 522276401238836 |
10 | 120122220000003 |
11 | 35302602679181 |
12 | 115805a8523143 |
13 | 5204627528ac0 |
14 | 2193d3717bdab |
15 | dd49c4478d53 |
hex | 6d402240b303 |
120122220000003 has 8 divisors (see below), whose sum is σ = 172483187692368. Its totient is φ = 73921366153824.
The previous prime is 120122219999987. The next prime is 120122220000089. The reversal of 120122220000003 is 300000022221021.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 120122220000003 - 24 = 120122219999987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (120122220000103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1540028461500 + ... + 1540028461577.
It is an arithmetic number, because the mean of its divisors is an integer number (21560398461546).
Almost surely, 2120122220000003 is an apocalyptic number.
120122220000003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120122220000003 is a deficient number, since it is larger than the sum of its proper divisors (52360967692365).
120122220000003 is a wasteful number, since it uses less digits than its factorization.
120122220000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3080056923093.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 120122220000003 its reverse (300000022221021), we get a palindrome (420122242221024).
The spelling of 120122220000003 in words is "one hundred twenty trillion, one hundred twenty-two billion, two hundred twenty million, three", and thus it is an aban number.
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