120122421113 has 2 divisors, whose sum is σ = 120122421114. Its totient is φ = 120122421112.

The previous prime is 120122420989. The next prime is 120122421131. The reversal of 120122421113 is 311124221021.

Together with next prime (120122421131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74775996304 + 45346424809 = 273452^2 + 212947^2 .

It is a cyclic number.

It is not a de Polignac number, because 120122421113 - 2¹⁴ = 120122404729 is a prime.

It is not a weakly prime, because it can be changed into another prime (120122421313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061210556 + 60061210557.

It is an arithmetic number, because the mean of its divisors is an integer number (60061210557).

Almost surely, 2^120122421113 is an apocalyptic number.

It is an amenable number.

120122421113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122421113 is an equidigital number, since it uses as much as digits as its factorization.

120122421113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 120122421113 its reverse (311124221021), we get a palindrome (431246642134).

The spelling of 120122421113 in words is "one hundred twenty billion, one hundred twenty-two million, four hundred twenty-one thousand, one hundred thirteen".