Base | Representation |
---|---|
bin | 1010111011001101010100… |
… | …0011011010001100000011 |
3 | 1120112100212001100021110002 |
4 | 2232303111003122030003 |
5 | 3033302144032002243 |
6 | 41314213102030215 |
7 | 2346601031543063 |
oct | 256632503321403 |
9 | 46470761307402 |
10 | 12012303000323 |
11 | 391143097a06a |
12 | 1420093b7836b |
13 | 6919a8562a32 |
14 | 2d75819513a3 |
15 | 15c703093eb8 |
hex | aecd50da303 |
12012303000323 has 2 divisors, whose sum is σ = 12012303000324. Its totient is φ = 12012303000322.
The previous prime is 12012303000289. The next prime is 12012303000329. The reversal of 12012303000323 is 32300030321021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12012303000323 - 28 = 12012303000067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12012303000295 and 12012303000304.
It is not a weakly prime, because it can be changed into another prime (12012303000329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006151500161 + 6006151500162.
It is an arithmetic number, because the mean of its divisors is an integer number (6006151500162).
Almost surely, 212012303000323 is an apocalyptic number.
12012303000323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012303000323 is an equidigital number, since it uses as much as digits as its factorization.
12012303000323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 12012303000323 its reverse (32300030321021), we get a palindrome (44312333321344).
The spelling of 12012303000323 in words is "twelve trillion, twelve billion, three hundred three million, three hundred twenty-three", and thus it is an aban number.
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