Base | Representation |
---|---|
bin | 110111111011111110… |
… | …0110110111110000111 |
3 | 102111001122120122200221 |
4 | 1233313330312332013 |
5 | 3432003223340033 |
6 | 131103443045211 |
7 | 11451533343136 |
oct | 1576774667607 |
9 | 374048518627 |
10 | 120124043143 |
11 | 46a42988615 |
12 | 1b345370807 |
13 | b434ac8690 |
14 | 5b579d591d |
15 | 31d0d0912d |
hex | 1bf7f36f87 |
120124043143 has 8 divisors (see below), whose sum is σ = 129514267008. Its totient is φ = 110755235424.
The previous prime is 120124043131. The next prime is 120124043147. The reversal of 120124043143 is 341340421021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120124043143 - 29 = 120124042631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120124043147) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5342380 + ... + 5364817.
It is an arithmetic number, because the mean of its divisors is an integer number (16189283376).
Almost surely, 2120124043143 is an apocalyptic number.
120124043143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120124043143 is a deficient number, since it is larger than the sum of its proper divisors (9390223865).
120124043143 is a wasteful number, since it uses less digits than its factorization.
120124043143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10708073.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 120124043143 its reverse (341340421021), we get a palindrome (461464464164).
The spelling of 120124043143 in words is "one hundred twenty billion, one hundred twenty-four million, forty-three thousand, one hundred forty-three".
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