Base | Representation |
---|---|
bin | 11011010100000010011010… |
… | …110111010000111100101101 |
3 | 120202022202200001212110002222 |
4 | 123110002122313100330231 |
5 | 111221103422314410013 |
6 | 1103252152102325125 |
7 | 34205455510500026 |
oct | 3324023267207455 |
9 | 522282601773088 |
10 | 120124243513133 |
11 | 35303450915582 |
12 | 11580a721297a5 |
13 | 520488a816652 |
14 | 2194089bd7c4d |
15 | dd4a91e33508 |
hex | 6d409add0f2d |
120124243513133 has 4 divisors (see below), whose sum is σ = 121226300793180. Its totient is φ = 119022186233088.
The previous prime is 120124243513111. The next prime is 120124243513159. The reversal of 120124243513133 is 331315342421021.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 56249670000484 + 63874573512649 = 7499978^2 + 7992157^2 .
It is a cyclic number.
It is not a de Polignac number, because 120124243513133 - 220 = 120124242464557 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 120124243513093 and 120124243513102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120124243513033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551028639860 + ... + 551028640077.
It is an arithmetic number, because the mean of its divisors is an integer number (30306575198295).
Almost surely, 2120124243513133 is an apocalyptic number.
It is an amenable number.
120124243513133 is a deficient number, since it is larger than the sum of its proper divisors (1102057280047).
120124243513133 is a wasteful number, since it uses less digits than its factorization.
120124243513133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1102057280046.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 120124243513133 its reverse (331315342421021), we get a palindrome (451439585934154).
The spelling of 120124243513133 in words is "one hundred twenty trillion, one hundred twenty-four billion, two hundred forty-three million, five hundred thirteen thousand, one hundred thirty-three".
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