Base | Representation |
---|---|
bin | 10110011000000011… |
… | …11101100100101011 |
3 | 1011000012120200101002 |
4 | 23030001331210223 |
5 | 144100312013003 |
6 | 5304012145215 |
7 | 603456552353 |
oct | 131401754453 |
9 | 34005520332 |
10 | 12013001003 |
11 | 5105031503 |
12 | 23b316820b |
13 | 1195a67323 |
14 | 81d643b63 |
15 | 4a498ca88 |
hex | 2cc07d92b |
12013001003 has 2 divisors, whose sum is σ = 12013001004. Its totient is φ = 12013001002.
The previous prime is 12013000999. The next prime is 12013001029. The reversal of 12013001003 is 30010031021.
12013001003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30010031021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12013001003 - 22 = 12013000999 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013006003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006500501 + 6006500502.
It is an arithmetic number, because the mean of its divisors is an integer number (6006500502).
Almost surely, 212013001003 is an apocalyptic number.
12013001003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013001003 is an equidigital number, since it uses as much as digits as its factorization.
12013001003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 12013001003 its reverse (30010031021), we get a palindrome (42023032024).
The spelling of 12013001003 in words is "twelve billion, thirteen million, one thousand, three".
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