Base | Representation |
---|---|
bin | 11011010100000111110011… |
… | …111000100101110101001011 |
3 | 120202100022121110221001202201 |
4 | 123110013303320211311023 |
5 | 111221202301143002311 |
6 | 1103254550321541031 |
7 | 34206052116021013 |
oct | 3324076370456513 |
9 | 522308543831681 |
10 | 120130032000331 |
11 | 3530595130a6a1 |
12 | 115820087a4777 |
13 | 52052a0b26ac2 |
14 | 21944788a8c43 |
15 | dd4cd01da9c1 |
hex | 6d41f3e25d4b |
120130032000331 has 2 divisors, whose sum is σ = 120130032000332. Its totient is φ = 120130032000330.
The previous prime is 120130032000323. The next prime is 120130032000343. The reversal of 120130032000331 is 133000230031021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120130032000331 - 23 = 120130032000323 is a prime.
It is a super-2 number, since 2×1201300320003312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120130032000299 and 120130032000308.
It is not a weakly prime, because it can be changed into another prime (120130032000311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065016000165 + 60065016000166.
It is an arithmetic number, because the mean of its divisors is an integer number (60065016000166).
Almost surely, 2120130032000331 is an apocalyptic number.
120130032000331 is a deficient number, since it is larger than the sum of its proper divisors (1).
120130032000331 is an equidigital number, since it uses as much as digits as its factorization.
120130032000331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 120130032000331 its reverse (133000230031021), we get a palindrome (253130262031352).
The spelling of 120130032000331 in words is "one hundred twenty trillion, one hundred thirty billion, thirty-two million, three hundred thirty-one", and thus it is an aban number.
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