12013010222131 has 16 divisors (see below), whose sum is σ = 12276345692160. Its totient is φ = 11749999861600.

The previous prime is 12013010222099. The next prime is 12013010222167. The reversal of 12013010222131 is 13122201031021.

It is a cyclic number.

It is not a de Polignac number, because 12013010222131 - 2⁵ = 12013010222099 is a prime.

It is a super-2 number, since 2×12013010222131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013010222099 and 12013010222108.

It is not an unprimeable number, because it can be changed into a prime (12013010262131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 553558581 + ... + 553580281.

It is an arithmetic number, because the mean of its divisors is an integer number (767271605760).

Almost surely, 2^{12013010222131} is an apocalyptic number.

12013010222131 is a deficient number, since it is larger than the sum of its proper divisors (263335470029).

12013010222131 is a wasteful number, since it uses less digits than its factorization.

12013010222131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28634.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12013010222131 its reverse (13122201031021), we get a palindrome (25135211253152).

The spelling of 12013010222131 in words is "twelve trillion, thirteen billion, ten million, two hundred twenty-two thousand, one hundred thirty-one".