120130231433 has 2 divisors, whose sum is σ = 120130231434. Its totient is φ = 120130231432.

The previous prime is 120130231423. The next prime is 120130231447. The reversal of 120130231433 is 334132031021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100976501824 + 19153729609 = 317768^2 + 138397^2 .

It is a cyclic number.

It is not a de Polignac number, because 120130231433 - 2³⁰ = 119056489609 is a prime.

It is a super-2 number, since 2×120130231433² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 120130231399 and 120130231408.

It is not a weakly prime, because it can be changed into another prime (120130231423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065115716 + 60065115717.

It is an arithmetic number, because the mean of its divisors is an integer number (60065115717).

Almost surely, 2^120130231433 is an apocalyptic number.

It is an amenable number.

120130231433 is a deficient number, since it is larger than the sum of its proper divisors (1).

120130231433 is an equidigital number, since it uses as much as digits as its factorization.

120130231433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120130231433 its reverse (334132031021), we get a palindrome (454262262454).

The spelling of 120130231433 in words is "one hundred twenty billion, one hundred thirty million, two hundred thirty-one thousand, four hundred thirty-three".