120130243410333 has 8 divisors (see below), whose sum is σ = 172494708486688. Its totient is φ = 73926303637104.

The previous prime is 120130243410319. The next prime is 120130243410343. The reversal of 120130243410333 is 333014342031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 120130243410333 - 2⁴⁵ = 84945871321501 is a prime.

It is a super-2 number, since 2×120130243410333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120130243410333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120130243410343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1540131325735 + ... + 1540131325812.

It is an arithmetic number, because the mean of its divisors is an integer number (21561838560836).

Almost surely, 2^{120130243410333} is an apocalyptic number.

120130243410333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

120130243410333 is a deficient number, since it is larger than the sum of its proper divisors (52364465076355).

120130243410333 is a wasteful number, since it uses less digits than its factorization.

120130243410333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3080262651563.

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 120130243410333 its reverse (333014342031021), we get a palindrome (453144585441354).

The spelling of 120130243410333 in words is "one hundred twenty trillion, one hundred thirty billion, two hundred forty-three million, four hundred ten thousand, three hundred thirty-three".