Base | Representation |
---|---|
bin | 11011010100001000000100… |
… | …101001101111011101101111 |
3 | 120202100100100002021121012221 |
4 | 123110020010221233131233 |
5 | 111221203340202222203 |
6 | 1103255034251340211 |
7 | 34206062103136606 |
oct | 3324100451573557 |
9 | 522310302247187 |
10 | 120130313320303 |
11 | 35305a86095540 |
12 | 11582086a51667 |
13 | 52053171b4220 |
14 | 21944a3db8a3d |
15 | dd4ce9c59abd |
hex | 6d4204a6f76f |
120130313320303 has 16 divisors (see below), whose sum is σ = 141390127622016. Its totient is φ = 100624360767840.
The previous prime is 120130313320289. The next prime is 120130313320351. The reversal of 120130313320303 is 303023313031021.
It is not a de Polignac number, because 120130313320303 - 25 = 120130313320271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120130313320103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 767812201 + ... + 767968642.
It is an arithmetic number, because the mean of its divisors is an integer number (8836882976376).
Almost surely, 2120130313320303 is an apocalyptic number.
120130313320303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120130313320303 is a deficient number, since it is larger than the sum of its proper divisors (21259814301713).
120130313320303 is a wasteful number, since it uses less digits than its factorization.
120130313320303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1535781414.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 120130313320303 its reverse (303023313031021), we get a palindrome (423153626351324).
The spelling of 120130313320303 in words is "one hundred twenty trillion, one hundred thirty billion, three hundred thirteen million, three hundred twenty thousand, three hundred three".
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