1201304112 has 40 divisors (see below), whose sum is σ = 3107997504. Its totient is φ = 399837504.

The previous prime is 1201304107. The next prime is 1201304119. The reversal of 1201304112 is 2114031021.

It is a junction number, because it is equal to n+sod(n) for n = 1201304091 and 1201304100.

It is not an unprimeable number, because it can be changed into a prime (1201304119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14463 + ... + 51105.

Almost surely, 2^1201304112 is an apocalyptic number.

1201304112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1201304112 is an abundant number, since it is smaller than the sum of its proper divisors (1906693392).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1201304112 is a wasteful number, since it uses less digits than its factorization.

1201304112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37337 (or 37331 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1201304112 is about 34659.8342754261. The cubic root of 1201304112 is about 1063.0433814256.

Adding to 1201304112 its reverse (2114031021), we get a palindrome (3315335133).

The spelling of 1201304112 in words is "one billion, two hundred one million, three hundred four thousand, one hundred twelve".