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12013100203 = 132803329677
BaseRepresentation
bin10110011000000100…
…10101110010101011
31011000012202201110011
423030002111302223
5144100323201303
65304014232351
7603460444516
oct131402256253
934005681404
1012013100203
115105099a95
1223b31b56b7
131195aa0520
1481d66bd7d
154a49ac16d
hex2cc095cab

12013100203 has 8 divisors (see below), whose sum is σ = 12941839568. Its totient is φ = 11085025824.

The previous prime is 12013100149. The next prime is 12013100213. The reversal of 12013100203 is 30200131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12013100203 - 229 = 11476229291 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013100213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128400 + ... + 201277.

It is an arithmetic number, because the mean of its divisors is an integer number (1617729946).

Almost surely, 212013100203 is an apocalyptic number.

12013100203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12013100203 is a deficient number, since it is larger than the sum of its proper divisors (928739365).

12013100203 is a wasteful number, since it uses less digits than its factorization.

12013100203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 332493.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 12013100203 its reverse (30200131021), we get a palindrome (42213231224).

The spelling of 12013100203 in words is "twelve billion, thirteen million, one hundred thousand, two hundred three".

Divisors: 1 13 2803 36439 329677 4285801 924084631 12013100203