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12013100149 is a prime number
BaseRepresentation
bin10110011000000100…
…10101110001110101
31011000012202201101011
423030002111301311
5144100323201044
65304014232221
7603460444411
oct131402256165
934005681334
1012013100149
115105099a46
1223b31b5671
131195aa04ab
1481d66bd41
154a49ac134
hex2cc095c75

12013100149 has 2 divisors, whose sum is σ = 12013100150. Its totient is φ = 12013100148.

The previous prime is 12013100119. The next prime is 12013100213. The reversal of 12013100149 is 94100131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10804147249 + 1208952900 = 103943^2 + 34770^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12013100149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013100119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006550074 + 6006550075.

It is an arithmetic number, because the mean of its divisors is an integer number (6006550075).

Almost surely, 212013100149 is an apocalyptic number.

It is an amenable number.

12013100149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013100149 is an equidigital number, since it uses as much as digits as its factorization.

12013100149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

The spelling of 12013100149 in words is "twelve billion, thirteen million, one hundred thousand, one hundred forty-nine".