120131100221 has 4 divisors (see below), whose sum is σ = 131052109344. Its totient is φ = 109210091100.

The previous prime is 120131100209. The next prime is 120131100251. The reversal of 120131100221 is 122001131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 120131100221 - 2¹⁰ = 120131099197 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 120131100196 and 120131100205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131100251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5460504545 + ... + 5460504566.

It is an arithmetic number, because the mean of its divisors is an integer number (32763027336).

Almost surely, 2^120131100221 is an apocalyptic number.

120131100221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

120131100221 is a deficient number, since it is larger than the sum of its proper divisors (10921009123).

120131100221 is a wasteful number, since it uses less digits than its factorization.

120131100221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10921009122.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120131100221 its reverse (122001131021), we get a palindrome (242132231242).

The spelling of 120131100221 in words is "one hundred twenty billion, one hundred thirty-one million, one hundred thousand, two hundred twenty-one".