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1201311044313 = 3400437014771
BaseRepresentation
bin10001011110110011101…
…101111101001011011001
311020211210102200001200020
4101132303231331023121
5124140241111404223
62315512532501053
7152535415252452
oct21366355751331
94224712601606
101201311044313
11423522848096
121749a477a789
138938b0bb983
14422026c2129
15213aed5d1e3
hex117b3b7d2d9

1201311044313 has 4 divisors (see below), whose sum is σ = 1601748059088. Its totient is φ = 800874029540.

The previous prime is 1201311044281. The next prime is 1201311044429. The reversal of 1201311044313 is 3134401131021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201311044313 - 25 = 1201311044281 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1201311044113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200218507383 + ... + 200218507388.

It is an arithmetic number, because the mean of its divisors is an integer number (400437014772).

Almost surely, 21201311044313 is an apocalyptic number.

It is an amenable number.

1201311044313 is a deficient number, since it is larger than the sum of its proper divisors (400437014775).

1201311044313 is an equidigital number, since it uses as much as digits as its factorization.

1201311044313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400437014774.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1201311044313 its reverse (3134401131021), we get a palindrome (4335712175334).

The spelling of 1201311044313 in words is "one trillion, two hundred one billion, three hundred eleven million, forty-four thousand, three hundred thirteen".

Divisors: 1 3 400437014771 1201311044313