120131130000 has 200 divisors, whose sum is σ = 443199980608. Its totient is φ = 27458496000.

The previous prime is 120131129957. The next prime is 120131130013. The reversal of 120131130000 is 31131021.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 76027 + ... + 496026.

Almost surely, 2^120131130000 is an apocalyptic number.

120131130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120131130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221599990304).

120131130000 is an abundant number, since it is smaller than the sum of its proper divisors (323068850608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131130000 is an equidigital number, since it uses as much as digits as its factorization.

120131130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 572091 (or 572070 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 120131130000 its reverse (31131021), we get a palindrome (120162261021).

The spelling of 120131130000 in words is "one hundred twenty billion, one hundred thirty-one million, one hundred thirty thousand".