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120131212133113 = 1929534113659971
BaseRepresentation
bin11011010100001000111010…
…001110011100001011111001
3120202100102122201120000121021
4123110020322032130023321
5111221212210301224423
61103255303400142441
734206123266002246
oct3324107216341371
9522312581500537
10120131212133113
11353063a7486945
1211582297a67a21
13520542b48341c
14219454b5065cd
15dd4d4daee95d
hex6d423a39c2f9

120131212133113 has 16 divisors (see below), whose sum is σ = 133282583092800. Its totient is φ = 107810800493760.

The previous prime is 120131212133081. The next prime is 120131212133137. The reversal of 120131212133113 is 311331212131021.

It is a cyclic number.

It is not a de Polignac number, because 120131212133113 - 25 = 120131212133081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120131212133173) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2056800783 + ... + 2056859188.

It is an arithmetic number, because the mean of its divisors is an integer number (8330161443300).

Almost surely, 2120131212133113 is an apocalyptic number.

It is an amenable number.

120131212133113 is a deficient number, since it is larger than the sum of its proper divisors (13151370959687).

120131212133113 is a wasteful number, since it uses less digits than its factorization.

120131212133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4113660072.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 120131212133113 its reverse (311331212131021), we get a palindrome (431462424264134).

The spelling of 120131212133113 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred twelve million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 19 29 53 551 1007 1537 29203 4113659971 78159539449 119296139159 218023978463 2266626644021 4142455590797 6322695375427 120131212133113