Base | Representation |
---|---|
bin | 11011010100001000111010… |
… | …001110011100001011111001 |
3 | 120202100102122201120000121021 |
4 | 123110020322032130023321 |
5 | 111221212210301224423 |
6 | 1103255303400142441 |
7 | 34206123266002246 |
oct | 3324107216341371 |
9 | 522312581500537 |
10 | 120131212133113 |
11 | 353063a7486945 |
12 | 11582297a67a21 |
13 | 520542b48341c |
14 | 219454b5065cd |
15 | dd4d4daee95d |
hex | 6d423a39c2f9 |
120131212133113 has 16 divisors (see below), whose sum is σ = 133282583092800. Its totient is φ = 107810800493760.
The previous prime is 120131212133081. The next prime is 120131212133137. The reversal of 120131212133113 is 311331212131021.
It is a cyclic number.
It is not a de Polignac number, because 120131212133113 - 25 = 120131212133081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120131212133173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2056800783 + ... + 2056859188.
It is an arithmetic number, because the mean of its divisors is an integer number (8330161443300).
Almost surely, 2120131212133113 is an apocalyptic number.
It is an amenable number.
120131212133113 is a deficient number, since it is larger than the sum of its proper divisors (13151370959687).
120131212133113 is a wasteful number, since it uses less digits than its factorization.
120131212133113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4113660072.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 120131212133113 its reverse (311331212131021), we get a palindrome (431462424264134).
The spelling of 120131212133113 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred twelve million, one hundred thirty-three thousand, one hundred thirteen".
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