Base | Representation |
---|---|
bin | 110111111100001100… |
… | …0010001100100110001 |
3 | 102111002011002210012212 |
4 | 1233320120101210301 |
5 | 3432012043330001 |
6 | 131104301101505 |
7 | 11451651415106 |
oct | 1577030214461 |
9 | 374064083185 |
10 | 120131230001 |
11 | 46a46a47172 |
12 | 1b347857895 |
13 | b436443963 |
14 | 5b58946aad |
15 | 31d17787bb |
hex | 1bf8611931 |
120131230001 has 2 divisors, whose sum is σ = 120131230002. Its totient is φ = 120131230000.
The previous prime is 120131229983. The next prime is 120131230013. The reversal of 120131230001 is 100032131021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84055925776 + 36075304225 = 289924^2 + 189935^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120131230001 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (120131230301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065615000 + 60065615001.
It is an arithmetic number, because the mean of its divisors is an integer number (60065615001).
Almost surely, 2120131230001 is an apocalyptic number.
It is an amenable number.
120131230001 is a deficient number, since it is larger than the sum of its proper divisors (1).
120131230001 is an equidigital number, since it uses as much as digits as its factorization.
120131230001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 120131230001 its reverse (100032131021), we get a palindrome (220163361022).
The spelling of 120131230001 in words is "one hundred twenty billion, one hundred thirty-one million, two hundred thirty thousand, one".
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