12013130009 has 2 divisors, whose sum is σ = 12013130010. Its totient is φ = 12013130008.

The previous prime is 12013129987. The next prime is 12013130089. The reversal of 12013130009 is 90003131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7224490009 + 4788640000 = 84997^2 + 69200^2 .

It is an emirp because it is prime and its reverse (90003131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12013130009 - 2¹² = 12013125913 is a prime.

It is a super-2 number, since 2×12013130009² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12013130089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006565004 + 6006565005.

It is an arithmetic number, because the mean of its divisors is an integer number (6006565005).

Almost surely, 2^12013130009 is an apocalyptic number.

It is an amenable number.

12013130009 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013130009 is an equidigital number, since it uses as much as digits as its factorization.

12013130009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

The spelling of 12013130009 in words is "twelve billion, thirteen million, one hundred thirty thousand, nine".