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120131300111 = 510712352241
BaseRepresentation
bin110111111100001100…
…0100010101100001111
3102111002011020100101112
41233320120202230033
53432012103100421
6131104302402235
711451652126364
oct1577030425417
9374064210345
10120131300111
1146a46a94909
121b34789037b
13b436469844
145b5896446b
1531d178e45b
hex1bf8622b0f

120131300111 has 4 divisors (see below), whose sum is σ = 120133703424. Its totient is φ = 120128896800.

The previous prime is 120131300039. The next prime is 120131300119. The reversal of 120131300111 is 111003131021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120131300111 is a prime.

It is a super-2 number, since 2×1201313001112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131300119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125050 + ... + 1227191.

It is an arithmetic number, because the mean of its divisors is an integer number (30033425856).

Almost surely, 2120131300111 is an apocalyptic number.

120131300111 is a deficient number, since it is larger than the sum of its proper divisors (2403313).

120131300111 is an equidigital number, since it uses as much as digits as its factorization.

120131300111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2403312.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 120131300111 its reverse (111003131021), we get a palindrome (231134431132).

The spelling of 120131300111 in words is "one hundred twenty billion, one hundred thirty-one million, three hundred thousand, one hundred eleven".

Divisors: 1 51071 2352241 120131300111